Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:
3N2H4(l)→4NH3(g)+N2(g)

A.) 2.0 mol N2H4

1) Use the balanced chemical equation to find the molar ratios (proportions) of each product and reactant.

3N2H4(l)→4NH3(g)+N2(g)

=> molar ratios: 3 mol N2H4 : 4 mol NH3

2) Use the product to reactant molar ratio, and the quantity of reactant to determine the yield:

2.0 mol N2H4 * [4mol NH3] / [3mol N2H4] = 2*4/3 mol NH3 = 2.7 mol NH3

Answer: 2.7 mol

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Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation: 3N2H4(l)→4NH3(g)+N2(g) A.) 2.0 mol N2H4

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Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:
3N2H4(l)→4NH3(g)+N2(g)

A.) 2.0 mol N2H4