gtzpw2m2yh gtzpw2m2yh
  • 14-08-2021
  • Mathematics
contestada

Find the center of a circle with the equation: x2+y2−4x+2y−11=0 x 2 + y 2 − 4 x + 2 y − 11 = 0

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xenia168
xenia168 xenia168
  • 14-08-2021

Answer:

( 2, - 1 )

Step-by-step explanation:

( x - h )² + ( y - k )² = r²

( h, k ) are coordinates of the center of a circle with radius r

~~~~~~~~~

x² + y² - 4x + 2y - 11 = 0

( x² - 4x + 4 ) - 4 + ( y² + 2y  + 1 ) - 1 - 11 = 0

( x - 2 )² + ( y + 1 )² = 4²

Coordinates of the center of a circle are ( 2, - 1 )

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