Seudónimo Seudónimo
  • 15-08-2021
  • Physics
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Help meh in this question​

Help meh in this question class=

Respuesta :

Аноним Аноним
  • 15-08-2021

  • Radius=r=R_o/2
  • angular velocity=w=v_o
  • mass=m

We know

[tex]\boxed{\sf K.E=\dfrac{1}{2}mv^2}[/tex]

For Rotational motion

[tex]\boxed{\sf v=r\omega}[/tex].

Putting value

[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m(r\omega)^2[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}mr^2\omega^2[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m\left(\dfrac{R_o}{2}\right)^2v_o^2[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{4}mv_o^2[/tex]

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