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15-12-2016
Mathematics

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Find the equation of the line that is perpendicular to y=3x+4 and that passes through the point (6,7)

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15-12-2016

The slope of the line perpendicular to y=3x+4 is -1/3 (negative reciprocal of 3).
so point (6,7) is on the line y=(-1/3)x + b
plug in x and y:
7=(-1/3)*6 +b
7= -2+b
b=9
[tex]y=-\frac{1}{3}x+9[/tex]

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