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[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]

  • Solve p/3<-6.

[tex] \huge \boxed{\mathfrak{Answer} \downarrow}[/tex]

[tex] \sf\frac { p } { 3 } \lt - 6 \\ [/tex]

Multiply both sides by 3. As 3 is >0, the inequality direction remains the same.

[tex] \sf \: p<-6\times 3 [/tex]

Multiply -6 and 3 to get -18.

[tex] \boxed{ \boxed{ \bf \: p<-18 }}[/tex]

msm555

Answer:

Solution given:

[tex]\frac{P}{3}<-6[/tex]

Multiplying both side by 3

[tex]\frac{P*3}{3}<-6*3[/tex]

P=-18

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