Answer:
The smallest integer is 8.
Step-by-step explanation:
Let the smallest integer be a.
The sum of 25 consecutive integers is 500.
n = 25, d = 1
Sn = n/2 x (2a + (n-1) x d)
500 = 25/2 x (2a + (25-1) x 1)
500 = 25/2 x (2a + 24)
1000 : 25 = 2 (a + 12)
40 : 2 = a + 12
20 - 12 = a
a = 8
