Solving Inequalities
Answer:
[tex](-\infty,-8][/tex]
Step-by-step explanation:
[tex]-2x +7 \geqslant 23 \\ -2x +7 -7 \geqslant 23 -7 \\ -2x \geqslant 16 \\ \frac{-2x}{-2} \leqslant \frac{16}{-2} \\ x \leqslant -8[/tex]
The values of [tex]x[/tex] has to be less than or equal to [tex]8[/tex] so [tex]x \in (-\infty,-8][/tex]
