jochosanchez1313 jochosanchez1313
  • 14-10-2021
  • Physics
contestada

Find the distance from a point charge q=100nC where the field intensity is equal to E=6kN/C. please include description of the result

Respuesta :

santy1508cech santy1508cech
  • 14-10-2021

Answer: 0.3872m

Explanation:

q= 100nC -->  100x10^-9 C

k= 9x10^9 Nm^2/C^2

E= 6kN/C --> 600 N/C

r=?

[tex]E= K\frac{q}{r^{2} }[/tex] --> [tex]r=\sqrt{\frac{kq}{E} }[/tex] Despejas "r"

Resuelves

[tex]r=\sqrt{\frac{(9x10^9 Nm^2/C^2)(100x10x^{-9} C)}{6000N/C} }[/tex]  (la x es por, no es una variable)

r= 0.3872983346m

Answer Link

Otras preguntas

Which of the following is a benefit of running? O A. Lower intensity than walking O B. Has no effect on abdominal and back muscles O C. Burns calories faster th
Jamal borrowed $15 600 for 6 years from a bank. The annual simple interest rate for the first 3 years is 1.6%. From then onward, the annual simple interest rate
What is the coefficient of the x to the power of 4 y to the power of 3 term in the expansion of (x-2y) the the power of 7?
Which equation would you use to find the distance between the two points? A. |2 - 4| B. |2 - (-4)| C. |-5 - 5| D. |2 + (-4)|
I really need help with this problem please A. hydrosphere. B. biosphere. C. lithosphere. D. atmosphere.
Help a killer is coming
Who is Keisha Alexinne Bertulfo
18. What events marked the end of the Soviet Union?
Could anyone check if I'm okay?
Evaluate the expression when у = 3 and z = 9. 2 y + (z-7)² x 2