miac119 miac119
  • 14-10-2021
  • Mathematics
contestada

X^4 y^6 x^-2
———————-
Y^3 y^2 x^8

Respuesta :

Аноним Аноним
  • 14-10-2021

Answer:

y^1 / x^4

Step-by-step explanation:

Formulas : -

p^q / p^r = p^( q - r )

p^q . p^r = p^( q + r )

p^-q = 1 / p^q

x^4 y^6 x^-2

------------------

y^3 y^2 x^8

= x^4 y^6 x^-2

------------------

y^3 y^2 x^8

= x^4 x^-2 y^6

------------------

y^3 y^2 x^8

= x^( 4 + ( - 2 ) ) y^6

-------------------------

y^( 3 + 2 ) x^8

= x^( 4 - 2 ) y^6

------------------

y^5 x^8

= x^2 y^6

------------------

x^8 y^5

= x^( 2 - 8 ) y^( 6 - 5 )

= x^-4 y^1

= y^1 / x^4

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