Respuesta :

mhanifa

Answer:

  • No, should be added

Step-by-step explanation:

The question is:

  • [tex](1/5)^2(1/5)^6 =[/tex]
  • [tex](1/5)^{2+6} =[/tex]
  • [tex](1/5)^8[/tex]

Use the rule:

  • [tex]a^ba^c= a^{b+c}[/tex]
DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

  • [tex]{{ \bigg(\dfrac{1}{5} \bigg) }^{2} \times \bigg( \dfrac{1}{5} \bigg) }^{6} [/tex]

  • [tex]{ \bigg( \dfrac{1}{5} \bigg) }^{2 + 6} [/tex]

  • [tex] {\bigg( \dfrac{1}{5} \bigg) }^{8} [/tex]

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