yop1010 yop1010
  • 03-01-2017
  • Physics
contestada


How high has a 45 g golf ball been driven if it has a potential energy of 2.06 J?

Respuesta :

Аноним Аноним
  • 03-01-2017
Here, U = mgh

We have: m = 45 g = 0.045 Kg
U = 2.06 J, g = 9.8 m/s², h = ?

Substitute the values in the formula:
2.06 = 0.045 × 9.8 × h
2.06 = 0.441 × h
h = 2.06 / 0.441
h = 4.67 m

In short, your final answer would be 4.67 meters

Hope this helps!

Answer Link
djsdoodle
djsdoodle djsdoodle
  • 03-01-2017
PE=mgh
2.06 J = 2.06 kg·m²/s² = (0.045 kg)·(9.8 m/s²)·h
where h is the height the ball has reached
Solve for h:
h = 2.06/(0.045·9.8) = 4.67 to the nearest hundredth
h = 4.67 m

Answer Link

Otras preguntas

Which of the following can penetrate the deepest (Please explain) A) 3MeV electron B) 10MeV alpha C) 0.1 MeV auger D) 400keV proton
1. How does wind help in the following activities?(a) Flying a kite(b) Moving a sailboat​
What concentration of Ni2+ ion remains in solution after electrolysis of 100. mL of 0.250 M NiSO4 solution when using a current of 2.40 amperes for 30.0 minutes
g(x) = 5x - 12. What is g(8)?
find the numberof moles in 60 grams of SO3
If a sound is 30 dB and its absolute pressure was 66 x 10-9 Pa, what must have been the reference pressure?
What are the differences between a Required RFC and an Elective RFC?
54/6 findind fraction of whole number
When a function uses a mixture of parameters with and without default arguments, the parameters with default arguments must be defined _________.
Solve the congruence 169x 25 (mod 330)