rileyferrier04 rileyferrier04
  • 13-12-2021
  • Mathematics
contestada

-
If AACB = ADCE, ZCAB = 50°,
ZDCE = 45°, and ZCDE = 10x
=
D
E
с
x = [?]

Please help

If AACB ADCE ZCAB 50 ZDCE 45 and ZCDE 10x D E с x Please help class=

Respuesta :

141500054 141500054
  • 14-12-2021

Answer:

∠BAC=70°

Step-by-step explanation:

If AB || CD and BC II DE that means the two triangles are congruent or the same, this means ∠BAC°=∠DCE°, ∠ABC°=∠EDC°, and ∠BCA°=∠DEC°. The three angles of a triagle add up to 180°. If ∠DEC=45° and ∠EDC=65°

Total°-(∠DEZ°+∠EDC°)=∠DCE° or ∠ECD°

180°-(65°+45°)=70°

∠BAC°=∠DCE°

Therefore ∠BAC=70°

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