Answer:
[tex](x-4)^{2}+(y-1)^{2} =4[/tex]
Step-by-step explanation:
we know that
The equation of a circle in center radius form is equal to
[tex](x-h)^{2}+(y-k)^{2} =r^{2}[/tex]
where
(h,k) is the center of the circle
r is the radius of the circle
In this problem we have
[tex](h,k)=(4,1)[/tex]
[tex]r=2\ units[/tex]
substitute
[tex](x-4)^{2}+(y-1)^{2} =2^{2}[/tex]
[tex](x-4)^{2}+(y-1)^{2} =4[/tex]
