Answer:
[tex]\huge\boxed{\sf x = 55\°}[/tex]
Step-by-step explanation:
When a quadrilateral is inscribed in a circle, the opposite angles of it add up to 180 degrees.
Here,
∠DCB + ∠DAB = 180 (Opposite angles of a quad inscribed in a circle.)
Given that: ∠DCB = 135° and ∠DAB = x
135 + x = 180
Subtract 135 to both sides
x = 180 - 135
x = 55°
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
