alexanderarmijo627 alexanderarmijo627
  • 14-01-2022
  • Mathematics
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P=16,000,r=4%,t=25 years;compounded continuously

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jdoe0001 jdoe0001
  • 14-01-2022

[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$16000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &25 \end{cases} \\\\\\ A=16000e^{0.04\cdot25}\implies A=16000e\implies A\approx 43492.51[/tex]

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