bkapschull bkapschull
  • 12-02-2022
  • Mathematics
contestada

Solve sin^2θ−4sinθ−5=0 for 0°≤θ≤360°

Solve sin2θ4sinθ50 for 0θ360 class=

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goddessboi goddessboi
  • 12-02-2022

Answer:

[tex]\theta=270^\circ[/tex]

Step-by-step explanation:

Given Equation and Parameters

[tex]sin^2\theta-4sin\theta-5=0,\: 0^\circ\leq\theta\leq 360^\circ[/tex]

Calculation

Let [tex]u=sin\theta[/tex], thus:

[tex]u^2-4u-5=0\\\\(u+1)(u-5)=0\\\\u=-1,\: u=5[/tex]

[tex]sin\theta=-1\\\\\theta=270^\circ[/tex]

[tex]sin\theta=5\\\\\theta=unde fined[/tex]

Conclusion

[tex]\theta=270^\circ[/tex]

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