Answer:
EY = 60
DW = 68
DE = 128
Step-by-step explanation:
Given
As YW is the perpendicular bisector of EF, then EY = FY
FY = √(FW² - YW²) = √(68² - 32²) = 60
⇒ EY = 60
As WX is the perpendicular bisector of DF, then DW = FW
As FW = 68, then DW = 68
As WZ is the perpendicular bisector of DE, then DZ = EZ = 64
Therefore, DE = DZ + EZ = 64 + 64 = 128
