Answer:
Step-by-step explanation:
1) [tex]\sf v_{f} =v_{i} +gt[/tex]
= 50 + (-9*8) *1
= 50 - 9.8
= 40.2 m/s
2) The acceleration of the ball at its maximum height equals to the force of gravity. -9.8 m/s²
3) The velocity at its top of the path:When the ball is thrown straight up, its velocity keeps on decreasing due the pull of gravity which pulls it towards the ground. So, the velocity at the top of its path is zero.
