Step-by-step explanation:
x² + x - 2 = 0
x² + 2x - x - 2 = 0
x(x + 2) - 1(x + 2) = 0
(x + 2)(x - 1) = 0
x + 2 = 0 and x - 1 = 0
x = -2 and x = 1
So, f(x) has no solution if x = -2 or 1
Domain = {x | x ≠ 2 and x ≠ 1}
