tmonet77 tmonet77
  • 11-06-2022
  • Mathematics
contestada

Divide (- 6 + i)/(1 - 2i) =

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loneguy
loneguy loneguy
  • 11-06-2022

[tex]~~~\dfrac{(-6 +i)}{(1- 2i)}\\\\\\=\dfrac{(-6+i)(1+2i)}{(1-2i)(1+2i)}\\\\\\=\dfrac{-6-12i+i+2i^2}{1-(2i)^2}\\\\\\=\dfrac{-6-11i-2}{1+4}~~~~~~~~~~~~~;[i^2=-1]\\\\\\=\dfrac{-8-11i}{5}\\\\\\=-\dfrac 85-\dfrac{11}{5}i[/tex]

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konrad509
konrad509 konrad509
  • 11-06-2022

[tex]\dfrac{-6+i}{1-2i}=\dfrac{(-6+i)(1+2i)}{(1-2i)(1+2i)}=\dfrac{-6-12i+i-2}{1+4}=\dfrac{-8-11i}{5}=-\dfrac{8}{5}-\dfrac{11}{5}i[/tex]

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