√6 is greater than √2+1.
Suppose that √6 is greater than √2+1. Then we check if our assumption is correct.
So √6 > √2+1
Squaring both sides and using the identity [tex](a+b)^2=a^2+b^2+2ab[/tex],
⇒ 6 > 3 + 2√2
Subtracting 3 from both sides,
⇒ 3 > 2√2
Again squaring on both sides,
⇒ 9 > 8
This is true. So our assumption is right.
Therefore, √6 > √2+1
Learn more about irrational numbers at https://brainly.com/question/16253673
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