so we gots apolynomial equation that is 3rd degree and crosses x axis at x=-1, x=0 and x=2
the factors of a poly equation that passes through r1,r2,r3 is
(x-r1)(x-r2)(x-r3)
so
r1=-1
r2=0
r3=2
f(x)=(x-(-1))(x-0)(x-2)
f(x)=(x+1)(x)(x-2)
f(x)=x³-x²-2x
leading coefient is posiitve because 3rd degree equations that are postive go bottom left to top right
yah
actually that looks like the exact graph
both
f(x)=(x+1)(x)(x-2)
and
f(x)=x³-x²-2x
are correct
