Given:
[tex]\frac{4+(\frac{2}{x})}{\frac{x}{3}+\frac{1}{6}}[/tex][tex]\frac{4+(\frac{2}{x})}{\frac{x}{3}+\frac{1}{6}}=\frac{\frac{4x+2}{x}}{\frac{2x+1}{6}}[/tex][tex]\frac{4+(\frac{2}{x})}{\frac{x}{3}+\frac{1}{6}}=\frac{4x+2}{x}\times\frac{6}{2x+1}[/tex][tex]\frac{4+(\frac{2}{x})}{\frac{x}{3}+\frac{1}{6}}=\frac{2(2x+1)}{x}\times\frac{6}{(2x+1)}[/tex][tex]\frac{4+(\frac{2}{x})}{\frac{x}{3}+\frac{1}{6}}=\frac{2}{x}\times\frac{6}{1}[/tex][tex]\frac{4+(\frac{2}{x})}{\frac{x}{3}+\frac{1}{6}}=\frac{12}{x}[/tex]