The distance across the river measured as x is 32 m
Here, we want to find the distance across the river;
That is the distance measured as x
We use the principle of similar triangles
When two triangles are similar, the ratio of corresponding sides are equal
We have this as;
[tex]\begin{gathered} \frac{10}{20}\text{ = }\frac{16}{x} \\ \\ 10\times x\text{ = 16}\times20 \\ \\ 10x\text{ = 320} \\ x\text{ = }\frac{320}{10}\text{ = 32 m} \\ \\ \end{gathered}[/tex]
