NazareneA352471 NazareneA352471
  • 03-11-2022
  • Mathematics
contestada

confused on perimeter

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DaileeJ42148 DaileeJ42148
  • 03-11-2022

The area will be, the area of the small square plus the area of the parallelogram plus the area of the rectangle.

The area of the square:

[tex]As=l\cdot l=2\cdot2=4in^2[/tex]

The area of the parallelogram:

[tex]Ap=B\cdot H=5\cdot3=15in^2[/tex]

The area of the rectangle:

[tex]Ar=l\cdot w=5\cdot2=10in^2[/tex]

Therefore:

[tex]\begin{gathered} A=As+Ap+Ar \\ A=4in^2+15in^2+10in^2 \\ A=29in^2 \end{gathered}[/tex]

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