BaneL124940 BaneL124940
  • 03-11-2022
  • Physics
contestada

Calculate the power of a 2057 Ω night light plugged into a 120 V source.

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AksharaG687926 AksharaG687926
  • 03-11-2022

Lets write the data down:

R = 2057 Ω

V = 120 V

The power of the night light is given by:

[tex]P=\frac{V^2}{R}[/tex]

Plug in the data in the formula:

[tex]\begin{gathered} P=\frac{120^2}{2057} \\ P=\frac{14,400}{2057} \\ P\approx7.0W \end{gathered}[/tex]

The power of the night light is 7.0 W.

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