Respuesta :

[tex]\bf (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad center\ ({{ h}},{{ k}})\qquad radius={{ r}}\\\\ -----------------------------\\\\ x^2+y^2=25\implies x^2+y^2=5^2\implies \begin{array}{llll} (x-&0)^2+(y-&0)^2=&5^2\\ &\uparrow &\uparrow &\uparrow \\ &h&k&r \end{array}[/tex]

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