nubunnebRaudy7 nubunnebRaudy7
  • 15-03-2017
  • Chemistry
contestada

A common cooking vinegar is 5.0% acetic acid (ch3cooh. how many molecules of acetic acid are present in 41.9 g vinegar?

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MissPhiladelphia
MissPhiladelphia MissPhiladelphia
  • 23-03-2017
To calculate the number of molecules ch3cooh in a given amount of vinegar, we first need to determine the amount of ch3cooh in the solution by multiplying the percent ch3cooh with the sample amount. Then, convert g to moles and use avogadro's number. We do as follows:

41.9 g vinegar solution ( .05 g 
ch3cooh / g vinegar solution ) (1 mol / 60.05 g ) ( 6.022x10^23 g / 1 mol ) = 2.1x10^22 molecules ch3cooh
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