We are given with the ionic equation
Li+(aq) + OH−(aq) + H+(aq) + Cl−(aq) → Li+(aq) + Cl−(aq) + H2O(l)
First, let us make sure that the equation is balanced. By inspection, the species on the left is balanced with the species on the right.
Next, we must identify any spectator ions. These are ions which are present in both the reactant and product side. The spectator ions are
Li+ (aq)
Cl−(aq)
Cancel out the spectator ions resulting in the net ionic equation.
OH−(aq) + H+(aq) → H2O(l)
