marianabanana marianabanana
  • 12-04-2017
  • Mathematics
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Sxerks Sxerks
  • 12-04-2017
From the right hand side, we will need to find a way to rewriting 3x²y in terms of cube roots.
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)

Hence, we can say that it's:
 [tex]\sqrt[3]{162x^{c}y^{5}} = \sqrt[3]{(3x^{2}y)^{3}} * \sqrt[3]{6y^{d}}[/tex]
[tex]= \sqrt[3]{162x^{6}y^{3+d}}[/tex]

Hence, c = 6 and d = 2
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