Respuesta :

icameforhelp
 H=-16+vt+c 
H=-16+128t+93 
0=-16+128t+93 
x=(-b±√(b^2-4ac))/2a 
x=(-128±√(〖128〗^2-4(-16)(93)))/(2(-16)... 

x=█(@-128±√1521852)/(-32) 

X1= -128+1233.63/-32 
= 1073.63 
X2=-128-1233.63/-32 
=-1393.63 


Substitute X2 into original eqtn to find “t” or time