Respuesta :

[tex] \frac{4}{3} v^2x - \frac{5}{6} vx^3[/tex]

[tex] \frac{4}{3} v^2x + \frac{-5}{6} vx^3[/tex]

Answer: [tex] \frac{-5}{6} vx^3 + \frac{4}{3} v^2x[/tex]
Panoyin
[tex]\frac{4}{3v^{2}x} - \frac{5}{6vx^{3}} = \frac{5(3v^{2}x)}{(3v^{2}x)(6vx^{3})} - \frac{4(6vx^{3})}{(3v^{2}x)(6vx^{3})} = \frac{15v^{2}x}{18v^{3}x^{4}} - \frac{24vx^{3}}{18v^{3}x^{4}} = \frac{15v^{2}x - 24vx^{3}}{18v^3x^{4}} = \frac{5v}{6x^{2}} - \frac{4}{3v^{2}x} [/tex]

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