[tex]\bf 2sin^2(x)=sin(x)\implies 2sin^2(x)-sin(x)=0
\\\\\\
sin(x)[2sin(x)-1]=0\implies
\begin{cases}
sin(x)=0\\
\measuredangle x = sin^{-1}(0)\\
\measuredangle x=0\ ,\ \pi \\
----------\\
2sin(x)-1=0\\
2sin(x)=1\\
sin(x)=\frac{1}{2}\\
\measuredangle x=sin^{-1}\left( \frac{1}{2} \right)\\
\measuredangle x =\frac{\pi }{6}\ ,\ \frac{5\pi }{6}
\end{cases}[/tex]
