12-07-2017
Mathematics

contestada

tan x =sin x/cos x. Therefore, tan(90-A) =
A) 1/tan(90-A)
B) 1/sin A
C) 1/cos(90-A)
D) 1/tanA

Respuesta :

wizard123 wizard123

12-07-2017

sin(90-A) = cos A
cos(90-A) = sin A

Therefore,

tan(90-A) = sin(90-A)/cos(90-A) = (cos A)/(sin A) = 1/(tan A)

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