Respuesta :

irspow
√((25x^9y^3)/(64x^6y^11))  doing the normal division within the radical

√((25x^3)/(64y^8)  then looking at the squares within the radical...

√((5^2*x^2*x)/(8^2*y^8))  now we can move out the perfect squares...

(5x/(8y^4))√x

So it is the bottom answer...

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