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01-08-2017
Chemistry

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20 g of nh4cl is added to 13.9 g of water. calculate the molality of the solution.

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Willchemistry Willchemistry

02-08-2017

Molar mass NH4Cl = 53.491 g/mol

number of moles solute :

n = m / mm

n = 20 / 53.491

n = 0.373 moles

solvent in kg :

13.9 / 1000 => 0.0139 kg

Therefore:

m = moles / volume

m = 0.373/ 0.0139

=> 26.83 molal

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