Answer:
To determine the number of isomers for C2HCl5, we can first identify the possible structural arrangements.
C2HCl5 can be represented as:
- Cl-CH(Cl)-CH(Cl)-CH2-Cl (1,1,1-trichloro-2,2-dichloroethane)
- Cl-CH2-CH(Cl)-CH2-Cl (1,1,2,2-tetrachloroethane)
So, there are two isomers for C2HCl5.
