Answer:
(1,13) and (4,7)
Explanation:
A stationary point of inflexion is a point on the graph with a second derivative of zero.
1st derivative:
f'(x) = [tex]4x^{3} - 30x^{2} + 4x + 3[/tex]
f"(x) = [tex]12x^{2} - 60x + 48[/tex]
Solve for [tex]12x^{2} - 60x + 48[/tex] = 0
x = 4
OR
x = 1
Using these two values of x-coordinates, sub into the original equation of f(x), you'll get:
when x = 4, y = 7
when x = 1, y = 13
