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  • 14-09-2015
  • Mathematics
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How many solutions does the equation have? 4x 1=5 2(2x-4)

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SchwarzschildRadius
SchwarzschildRadius SchwarzschildRadius
  • 15-09-2015
So,

4x + 1 = 5 + 2(2x - 4)
4x + 1 = 5 + 4x - 8
4x + 1 = 4x - 3
1 = -3 FALSE

There are ZERO solutions to this equation.
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