shephardstachu shephardstachu
  • 01-11-2017
  • Mathematics
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-1/3 |h|^2- 2/3 y^3 -2/3 〖|b|〗^3

b = - 1/2 h = 1 1/2 y = -2

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sthefanymorriss
sthefanymorriss sthefanymorriss
  • 08-11-2017
[tex]-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3[/tex]
[tex]\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|=\frac{1}{12} [/tex]
[tex]\frac{2}{3}\left|-\frac{1}{2}\right|^3=\frac{1}{12}[/tex]
[tex]=-\frac{1}{12}-\frac{2}{3}-2^3-\frac{1}{12}[/tex]
[tex]=-\frac{53}{6} [/tex]
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