[tex]\bf \qquad \textit{Amount for Exponential Decay}\\\\
y=I(1 - r)^x\qquad
\begin{cases}
y=\textit{accumulated amount}\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
x=\textit{elapsed time}\\
\end{cases}
\\\\\\
y=(0.94)^x\implies y=(1~-~\stackrel{r}{0.06})^x
\\\\\\
r=0.06\implies r\%=0.06\cdot 100\implies r=\stackrel{\%}{6}[/tex]
