notagnes notagnes
  • 16-02-2018
  • Mathematics
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Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 23-03-2019

Answer:

  sin(x)cos(x) = -4/9

Step-by-step explanation:

Square the given equation, and solve for the desired product.

  (sin(x) +cos(x))^2 = (1/3)^2

  sin(x)^2 +2sin(x)cos(x) +cos(x)^2 = 1/9

  1 + 2sin(x)cos(x) = 1/9 . . . use the trig identity for sin²+cos²

  2sin(x)cos(x) = -8/9 . . . . . subtract 1

  sin(x)cos(x) = -4/9 . . . . . . divide by 2

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