Hello!
To know how many grams of Ammonium Chloride ( a solid) you'll need to make 1.50 L of a 0,01 M solution you'll need to use the definition of molar concentration (M=mol/L) in the following way:
[tex]1,50 L* \frac{0,01 mol NH_4Cl}{1L}* \frac{53,489gNH_4Cl}{1 mol NH_4Cl}=0,8023 g NH_4Cl [/tex]
So, you'll need to dissolve 0,8023 g of Ammonium Chloride in 1,5 L of water to make this solution.
Have a nice day!
