hayleelaguerre hayleelaguerre
  • 15-03-2018
  • Physics
contestada

an object possessing an excess of 6.0x10^6 electrons has a net charge of

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skyluke89
skyluke89 skyluke89
  • 24-03-2018
A single electron has a charge of
[tex]e=-1.6 \cdot 10^{19}C[/tex]
Therefore, if we have an excess of [tex]N=6.0\cdot10^6[/tex] electrons, the total net charge will be the product between the charge of a single electron and the total number of electrons in excess:
[tex]Q=Ne=(6.0\cdot10^6)(-1.6 \cdot 10^{-19}C)=9.6 \cdot 10^{-13}C[/tex]
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