[tex]\displaystyle V= \frac{1}{3}S \cdot h, [/tex]
The base of this pyramid is a right triangle. So:
S=(18×10)÷2=180÷2=90 (cm²)
h is 11 cm. We can find the volume:
[tex]\displaystyle V= \frac{90 \cdot 11}{3}=30 \cdot 11=330 (cm^3)[/tex]
The volume of this triangular pyramid is 330 cubic centimeters
