Respuesta :

SINAZEUS
the answer is 400in^2

work :

you can separate this figure into two regular figures: a parallelogram and a right triangle

let's find the area of the parallelogram
(height x side)

[tex]16 \times 20 = 320[/tex]
and now we can find the area of the right triangle (height x side /2

[tex](8 \times 20) \div 2 = 160 \div 2 = 80[/tex]

so the area of the whole shape is :
[tex]320 + 80 = 400[/tex]




good luck

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