dtrdtrdtrdtrdrt9971 dtrdtrdtrdtrdrt9971
  • 01-05-2018
  • Chemistry
contestada

a gas is contained in a thick walled balloon. when the pressure changes from 417 mm hg to 576 mm hg, the volume changes from l to 4.78 l and the temperature changes from 497 k to 386k

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blahblahmali blahblahmali
  • 12-05-2018
we can use the combined gas law equation to solve for the initial volume
[tex] \frac{P1V1}{T1} = \frac{P2V2}{T2} [/tex]
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting the values in the equation 
[tex] \frac{417 mmHg*V}{497 K} = \frac{576mmHg*4.78L}{386K} [/tex]
V = 8.50 L
the initial volume is 8.50 L
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RahmaHadi745
RahmaHadi745 RahmaHadi745
  • 11-12-2020

Answer:

8.50 L

Explanation:

Answer Link

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