yami151 yami151
  • 02-05-2018
  • Mathematics
contestada

how can you solve p2 - 12 =p ?

Respuesta :

Аноним Аноним
  • 02-05-2018
P= 4 and -3
Move all the terms to the left side and set equal to zero. Then set each factor to zero.
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Allysia123
Allysia123 Allysia123
  • 02-05-2018

[tex] - {p}^{2} - 12 = p \\ {p}^{2} - 12 - p = 0 \\ {p}^{2} - p - 12 = 0[/tex]

Now, use the mid term splitting technique

[tex] {p}^{2} - 4p + 3p - 12 \\ = p(p - 4) + 3(p - 4) \\ = (p + 3)(p - 4) \\ \\ \\ \\ [/tex]


From here
we'll do the same thing we do to find the zeroes,


p+3=0 or p -4 =0

p = -3 or p = 4

Therefore
p = -3 and 4



Answer Link

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