We will use the quadratic formula to find these: [tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}
\\
\\=\frac{-9\pm \sqrt{9^2-4(7)(1)}}{2(7)}=\frac{-9\pm \sqrt{81-28}}{14}
\\
\\=\frac{-9\pm \sqrt{53}}{14}=\frac{-9+\sqrt{53}}{14}\text{ or } \frac{-9-\sqrt{53}}{14}
\\
\\=-0.1\text{ or }-1.2[/tex]
