jmorales48 jmorales48
  • 11-07-2018
  • Physics
contestada

a beetle crawls from x=1.09m to x=2.55m in 12.8s. what was the average velocity?

Respuesta :

skyluke89
skyluke89 skyluke89
  • 20-07-2018

The average velocity of the beetle is equal to the ratio between the displacement and the time:

[tex] v=\frac{S}{t} [/tex]


The displacement of the beetle is

[tex] S=2.55 m-1.09 m=1.46 m [/tex]

The time is t=12.8 s


Therefore, the average velocity is

[tex] v=\frac{S}{t}=\frac{1.46 m}{12.8 s}=0.11 m/s [/tex]

in the positive x-direction.

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